The graph of which function will have a maximum and a y-intercept of 4?
0 fx) = 4x + 6x-1
f(x) = -4x2 + 8x + 5
f(x) ==x2 + 2x + 4
0 f(x)= x2 + 4x-4

Step-by-step explanation:

We have quadratic functions f(x) = ax² + bx + c.

c - y-intercept

If a > 0, then a parabola opens up and has a minimum in a vertex.

If a < 0, then a parabola opens down and has a maximum in a vertex.

The function has maximum and y-intercept of 4:

a < 0 and c = 4

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length