The montanez family is a family of four people. they have used 3,485.78 gallons of water so far this month. they cannot exceed 7,250.50 gallons per month during drought season. write an inequality to show how much water just one member of the family can use for the remainder of the month, assuming each family member uses the same amount of water every month.

4x + 3,485.78 ≤ 7,250.50
4x − 3,485.78 ≤ 7,250.50
4x − 3,485.78 ≥ 7,250.50
4x + 3,485.78 ≥ 7,250.50

4x+3485.78≤ 7250.50

Step-by-step explanation:

The family cannot use more than 7250.5 gallons

Let the total family water used be y

Water used per person from now on be x

y=4x+3485.78

y≤ 7250.50

Substitute the answer into the inequality

4x+3485.78≤ 7250.50

Step-by-step explanation:

Let x be the amount of water used for the remainder of the month by each member of the family.

Given : The Montanez family is a family of four people.

Then , the total amount of water used for the remainder of the month by family is given by the expression :-

Then , the inequality to show how much water just one member of the family can use for the remainder of the month is given by :-

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

25/6

step-by-step explanation:

you multiply 4 by the denominator (4*6=24) and add it to the numerator which makes it 25/6.