It is known that for all tests administered last year, the distribution of scores was approximately normal with mean 74 and standard deviation 7.1. a. a particular employer requires job candidates to score at least 80 on the dexterity test. approximately what percentage of the test scores during the past year exceeded 80?

19.77%

Step-by-step explanation:

Given: Mean :

Standard deviation :

The formula to calculate z-score is given by :_

For x= 80, we have

The P-value =

In percent ,

Hence, the approximate percentage of the test scores during the past year exceeded 80 =19.77%

4.08%

step-by-step explanation:

$97520

step-by-step explanation:

add 6% to the value she got from selling the house.