Which function has an axis of symmetry of x = −2?

f(x) = (x − 1)2 + 2
f(x) = (x + 1)2 − 2
f(x) = (x − 2)2 − 1
f(x) = (x + 2)2 − 1

Step-by-step explanation:

Suppose a function is given in this form y = (x-c)^2 where c is a constant.

We can say that x = c is the axis of symmetry

If the function was given in the form y = (x+c)^2 where c is a constant,

We can say that x = -c is the axis of symmetry.

So, from the answer choices, we see that:

f(x) = (x − 2)^2 − 1 will have axis of symmetry at x = 2, and

f(x) = (x + 2)2 − 1 will have axis of symmetry at x = -2

Thus the last option is right.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

answer. d.289 hope that