The perimeter of a rectangle can be found using the equation p = 2l + 2w, where p is the perimeter, l is the length, and w is the width of the rectangle. can the perimeter of the rectangle be 60 units when its width is 11 units and its length is 24 units?
no. if the length is 24 units and the width is 11 units, the perimeter would be p = 48 + 22 = 70 units, not 60.
no. if the length is 24 units and the width is 11 units, the perimeter would be p = 24 + 22 = 66 units, not 60.
yes. if the perimeter is 60 units and the width is 11 units, then p + w is greater than 48.
yes. if the length is 24 units and the width is 11 units, then p = 2l + 2w = 60.

Each of the following data sets has a mean of x = 10. (i) 8 9 10 11 12 (ii) 7 9 10 11 13 (iii) 7 8 10 12 13 (a) without doing any computations, order the data sets according to increasing value of standard deviations. (i), (iii), (ii) (ii), (i), (iii) (iii), (i), (ii) (iii), (ii), (i) (i), (ii), (iii) (ii), (iii), (i) (b) why do you expect the difference in standard deviations between data sets (i) and (ii) to be greater than the difference in standard deviations between data sets (ii) and (iii)? hint: consider how much the data in the respective sets differ from the mean. the data change between data sets (i) and (ii) increased the squared difference îł(x - x)2 by more than data sets (ii) and (iii). the data change between data sets (ii) and (iii) increased the squared difference îł(x - x)2 by more than data sets (i) and (ii). the data change between data sets (i) and (ii) decreased the squared difference îł(x - x)2 by more than data sets (ii) and (iii). none of the above