![f(x)=7(b)^{x}-2](/tpl/images/0023/9134/c52a7.png)
![f(x)=-5(b)^{x}+10](/tpl/images/0023/9134/38696.png)
Step-by-step explanation:
we know that
The y-intercept is the value of y when the value of x is equal to zero
Verify each case
case 1) we have
![f(x)=7(b)^{x}-2](/tpl/images/0023/9134/c52a7.png)
so
For x=0
![f(0)=7(b)^{0}-2](/tpl/images/0023/9134/f29c8.png)
![f(0)=7(1)-2=5](/tpl/images/0023/9134/f6298.png)
therefore
The function has a y-intercept of (0,5)
case 2) we have
![f(x)=3(b)^{x}-5](/tpl/images/0023/9134/48363.png)
so
For x=0
![f(0)=3(b)^{0}-5](/tpl/images/0023/9134/d8645.png)
![f(0)=3(1)-5=-2](/tpl/images/0023/9134/51c7e.png)
therefore
The function does not have a y-intercept of (0,5)
case 3) we have
![f(x)=5(b)^{x}-1](/tpl/images/0023/9134/26176.png)
so
For x=0
![f(0)=5(b)^{0}-1](/tpl/images/0023/9134/e5df0.png)
![f(0)=5(1)-1=4](/tpl/images/0023/9134/d2575.png)
therefore
The function does not have a y-intercept of (0,5)
case 4) we have
![f(x)=-5(b)^{x}+10](/tpl/images/0023/9134/38696.png)
so
For x=0
![f(0)=-5(b)^{0}+10](/tpl/images/0023/9134/a75fb.png)
![f(0)=-5(1)+10=5](/tpl/images/0023/9134/0287f.png)
therefore
The function has a y-intercept of (0,5)
case 5) we have
![f(x)=2(b)^{x}+5](/tpl/images/0023/9134/335b1.png)
so
For x=0
![f(0)=2(b)^{0}+5](/tpl/images/0023/9134/ac07e.png)
![f(0)=2(1)+5=7](/tpl/images/0023/9134/d5f03.png)
therefore
The function does not have a y-intercept of (0,5)