Aregular octagon has an apothem measuring 10 in, and a
perimeter of 66.3 in
what is the area of the octagon, rounded to the nearest
square inch?
10 in
88 in 2
175 in 2
332 in2
700 in 2

Option C. 332 in²

Step-by-step explanation:

In the figure attached, a regular octagon has been drawn with all equal sides and apothem OP = 10 in.

Perimeter of the given octagon is given as 66.3 in

We have to calculate the area of the octagon.

As we can see in the figure an octagon is a combination of 8 triangles.

So we will find the area of one triangle first.

Area of ΔBOC =

Since perimeter of octagon = 8 × one side = 8×BC

66.3 = 8× BC

BC =

BC = 8.288 in

Therefore, area of ΔBOC =

= 5×8.288

= 41.44 in²

Now area of octagon ABCDEFGH = 8×41.44 = 331.5 ≈ 332 in²

Therefore, area of the regular octagon will be 332 in²

Option C. is the answer.

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it