y ≥-1/3 x + 2
y < 2x + 3
(2, 2), (3, 1), (4, 2)
(2, 2), (3, –1), (4, 1)
(2, 2), (1, –2), (0, 2)
(2, 2), (1, 2), (2, 0)

(2, 2), (3, 1), (4, 2)

Step-by-step explanation:

y ≥-1/3 x + 2

y < 2x + 3

(2, 2), (3, 1), (4, 2)

(2, 2), (3, –1), (4, 1)

(2, 2), (1, –2), (0, 2)

(2, 2), (1, 2), (2, 0)

I will assume which we determining which set of points is a solution

(2,2) is in all the sets, so we ignore it

Looking at the graph, we do not have negative solutions for y when x >0 so (3,-1) cannot be a solution and (1,-2) cannot be a solution

(2, 2), (3, 1), (4, 2)

(2, 2), (3, –1), (4, 1)   x

(2, 2), (1, –2), (0, 2)   x

(2, 2), (1, 2), (2, 0)

Again looking at the graph (2,0) is not a solution

(2, 2), (3, 1), (4, 2)

(2, 2), (3, –1), (4, 1)   x

(2, 2), (1, –2), (0, 2)   x

(2, 2), (1, 2), (2, 0)  x

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