The sum of the measures of two complementary angles exceeds the difference of their measures by 72°. find the measure of the smaller angle

Complementary angles are pair of two non-right angles whose sum is equal to 90°

Let the two complementary angles be : Δ and Ф

Given : Sum of the measures of two complementary angles exceed the difference of their measures by 72°

 Δ + Ф - 72° = Δ - Ф

 2Ф = 72°

 Ф = 36°

As Δ and Ф are complementary, their sum should be equal to 90°

 Δ + 36° = 90°

 Δ = 90° - 36°

 Δ = 54°

So, Complementary angles are 54° and 36°

Answer : The Measure of the Smaller Angle is 36°

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step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

step-by-step explanation:

first, eliminate the parenthesis:

3

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2

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second, group like terms:

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4

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third, combine like terms:

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3

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1

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2