Graph aabc with vertices ac-3, 4), b(-1,2), and c(-2,0) and its image after a 270° rotation about the origin.

Here's what I get.

Step-by-step explanation:

The formula for rotation of a point (x,y) by an angle θ about the origin is  

x' = xcosθ  -  ysinθ

y' = ycosθ + xsinθ

If θ = 270°, sinθ = -1 and cosθ = 0, and the formula becomes

x' =    y

y' =  -x

A: (-3,4)  ⟶ (4,3)

B: (-1,2)   ⟶ (2,1)

C: (-2,0) ⟶ (0,2)  

The vertices of A'B'C' are (4,3), (2, 1), and (0, 2).

The Figure below shows the triangle before and after the rotation.

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