Suppose that 45% of all adults regularly consume coffee, 40% regularly consume carbonated soda, and 55% regularly consume at least one of these two products. (a) what is the probability that a randomly selected adult regularly consumes both coffee and soda? (b) what is the probability that a randomly selected adult doesn't regularly consume at least one of these two products?

a) 30% and b) 45%

Step-by-step explanation:

Since we have given  that

Probability that adults regularly consume coffee P(C) = 45% = 0.45

Probability that adults regularly consume carbonated soda P(S) = 40% = 0.40

Probability that adults regularly consume atleast one of these two products P(C∪S) = 55% = 0.55

a) What is the probability that a randomly selected adult regularly consumes both coffee and soda?

As we know that

P(C∪S ) = P(C) +P(S)-P(C∩S)

b) What is the probability that a randomly selected adult doesn't regularly consume at least one of these two products?

P(C∪S)'=n(U)-P(C∪S)

Hence, a) 30% and b) 45%

after simplifying it i got: -36.25 as my answer. hope that !

44

step-by-step explanation: