Mathematics, 29.06.2019 03:10 shongmadi77
Line jk passes through points j(-4,-5) and k(-6,3). if the equation of the line is written in slope-intercept form, y = mx + b
what is the value of b?
-21
4
11
27
Answers: 1
![\bf J(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-5})\qquad K(\stackrel{x_2}{-6}~,~\stackrel{y_2}{3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-(-5)}{-6-(-4)}\implies \cfrac{3+5}{-6+4}\implies \cfrac{8}{-2}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-5)=-4[x-(-4)]\implies y+5=-4(x+4)](/tpl/images/0029/5180/9edc4.png)
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Line jk passes through points j(-4,-5) and k(-6,3). if the equation of the line is written in slope-...
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