What are the zeros of the function shown in the graph?
the graph starts at the bottom left, continues up through the x axis at negative three to a maximum around y equals three, goes back down through the x axis at negative one to a minimum around y equals negative one, and goes back up through the x axis at one.
a. −1, 1, 2
b. −2, −1, 1
c. −3, −1, 1
d. −1, 1, 3

The zeroes of the function are -3 , -1 , 1 ⇒ 3rd answer

Step-by-step explanation:

* Lets explain the meaning of the zeroes of the function

- The zeroes of the function are the values of x when f(x) = 0

- That means the coordinates of the intersection points between the

 curve and the x-axis

- Ex: If the graph of f(x) intersects the x-axis at points (p , 0) , (q , 0) ,

 (r , 0) then the zeroes of f(x) are p , q , r

* Lets solve the problem

- The graph starts at the bottom left

- It continues up through the x-axis at negative three

- That means it intersects the x-axis at point (-3 , 0)

∴ The first zero of the function is -3

- It goes to a maximum around y equals three

- It goes back down through the x-axis at negative one

- That means it intersects the x-axis again at point (-1 , 0)

∴ The second zero of the function is -1

- It goes to a minimum around y equals negative one

- It goes back up through the x-axis at one

- That means it intersects the x-axis again at point (1 , 0)

∴ The third zero of the function is 1

∴ The function has three zeroes -3 , -1 , 1

* The zeroes of the function are -3 , -1 , 1

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.