Asap (99 ! )
select the correct answers
∆abc has vertices at a(11, 6), b(5, 6), and c(5, 17).
∆xyz has vertices at x(-10, 5), y(-12, -2), and z(-4, 15).
∆mno has vertices at m(-9, -4), n(-3, -4), and o(-3, -15).
∆jkl has vertices at j(17, -2), k(12, -2), and l(12, 7).
∆pqr has vertices at p(12, 3), q(12, -2), and r(3, -2).
(∆abc and ∆xyz), (∆abc and ∆mno), (∆jkl and ∆abc), (∆pqr and ∆xyz) can be shown to be congruent by a sequence of reflections and translations.
(∆abc and ∆xyz), (∆pqr and ∆qyz), (∆jkl and ∆pqr), (∆jkland ∆xyz) can be shown to be congruent by a single rotation.