Kevin is responsible for delivering sacks of grains to a grocery shop on the tenth floor of a departmental store. each sack weighs 364 pounds and kevin weighs 150 pounds. the capacity of the elevator is 2,000 pounds.
if six sacks are to be taken at a time, what should be the weight of each sack?

The answer is:

If six sacks are to be taken at a time, the weight of each sack should be at most 308 pounds.

To calculate the weight that each sack should have, we first need to calculate how many pounds of the elevator capacity are free after is on it.

We know that Kevin weighs 150 pounds and the capacity of the elevator is 2000 pounds, so, calculating we have:

Now that we already know that there are 1850 pounds left to take the delivering sacks, we need to divide it by the number of sacks that need to be taken at a time, so:

So, we have that if six sacks are to be taken at a time, the weight of each sack should be at most 308 pounds.

Have a nice day!

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic