The compound cd undergoes dissociation in aqueous solution to produce c and d ions. at equilibrium (25 c), the concentrations of the both ions is 1.22x 10 m. given the standard enthalpy for this dissociation is 22.2 kj/mol, calculate the equilibrium constants for this dissociation process at 25 "c and 50 °c.

the answer is 13 cm

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

whaere is the picture

step-by-step explanation:

ιт ιѕ в. 1/4

ιи (fяα¢тισи/єχα¢т fσям) 1/4

ιи (∂є¢ιмαℓ fσям) .25

нσρє ι ¢συℓ∂ нєℓρ уα