Based on a comcast survey, there is a 0.8 probability that a randomly selected adult will watch prime-time tv live, instead of online, on dvr, etc. assume that seven adults are randomly selected. find the probability that fewer than three of the selected adults watch prime-time live.

Our required probability is 0.004672.

Step-by-step explanation:

Since we have given that

Number of adults = 7

Probability of getting adult will watch prime time TV live = 0.8

We need to find the probability that fewer than 3 of the selected adults watch prime time live.

We will use "Binomial Distribution":

here, n = 7

p = 0.8

So, P(X<3)=P(X=0)+P(X=1)+P(X=2)

So, it becomes,

So, probability that fewer than 3 of the selected adult watch prime time live is given by

Hence, our required probability is 0.004672.

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step-by-step explanation:

steve should create a type of business report called a business plan. the correct option among the options that are already given in the question is the last or the fourth option. this business report created by steve will actually influence the investors about investing their money in steve's business. this business report will have all the details about the business, the amount of investment required and the amount of expected profit.