Bradley is preparing a presentation to show the ceo of his company. he wants to emphasize that the profits of their competitor have increased slowly over the past 16 months.
the graphs below show the profit, y, of the competitor over the past 16 months. both graphs show the same information.
complete the following sentences.
to emphasize the slow increase in profits, it would be best for bradley to use for his presentation.
bradley should use this graph for his presentation because the profit on this graph.
1)
a. graph a
b. graph b
2)
a. increases more
b. is less
c. increases less
d. appears to increase more
e. appears to increase less

This is about steepness of Graphs.

A) Graph A

B) appears to increase less

For Graph A; at 0 months, the profit was around $10,500 while at the 16th month, it was around $17000, This indicates an increase of $6500 over a period of sixteen months.

For Graph B; at 0 months, the profit was around $11,500 while at the 16th month, it was around $18000, This indicates an increase of $6500 over a period of sixteen months.

However, since he wants to show that the profit increase is slow, it will be better to use Graph A because it appears less steeper than that of graph B.

Read more at;  link

1)  A. graph A

2)  E. appears to increase less

Step-by-step explanation:

The vertical scale extends farther on graph A, so the vertical extent of the plotted data is a smaller portion of it, making it look like the competitor's profit hasn't increased much.

This is how you can use the scale of a graph to influence the way the graphed data is interpreted. The practice is all too common.

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.