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Mathematics, 03.07.2019 17:10 jarviantemelton

Pgp encryption here is the set up of this certificate of authority: e= 120-r- 4897, and the two (mod iverses: 129, 1401 to receive enarypied messages, olivia posts these values of n and e to a public key encryption service, called a certificate authority, which guarantees the integrity of her public key if henry wants to send olivia a message, he codes his message as a number using a number for each letter of the alphabet. for instanoe, he might use a 11, b 12, c = 13, ., and z 36. for henry to send the message math, he would use the numbers 23 11 30 18 and code those numbers using olivia's public key, n 129 mod 4897 m, where n is the plaintext (2311 30 18), and mis the ciphertext, the result of using the modular equation. this is shown below. (can you calculate 23^129 on your calculator? ! it has 175 digits! and we need all of them) =3065 =2001 957 (can you calculate 23129 on your calculator? ! it has 190 digits! =2753 henry sends olivia the ciphertext numbers 3065, 2001, 957, and 2753. when olivia receives the message, she uses her private key, m1401 mod 4897 n, where mis the ciphertext she received from henry and n is the ariginal plaintext, to decode the message. olivia calculates 3065 1401 mod 4897 23, 2001 1401 mod 4897 11, 957 1401 mod 4897 30, 2753 1401 mod 4897 18. olivia decodes the message as 23 11 30 18 or math for the following, use the values for n, e, and d that we used above. encrypt the wereeotscbeidunasoxablea." using a 11, b 12, c 13, ., and z 36. then decode it as above

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