For the following, work each by hand showing all steps. (4 points each)
if a dealer is dealing a card game where a player receives 5 cards from a standard 52-card deck, find the following probability. (6 points)
probability of 3 clubs and 2 red cards?

0.0358

Step-by-step explanation:

In a 52 deck, 13 cards are Clubs, and 26 cards are red.

There are ₁₃C₃ ways to choose 3 Clubs from 13.

There are ₂₆C₂ ways to choose 2 red cards from 26.

There are ₅₂C₅ ways to choose 5 cards from 52.

P = (₁₃C₃ ₂₆C₂) / ₅₂C₅

P = (286 × 325) / 2598960

P = 0.0358

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!