Suppose we represent the distance above the ground by a positive integer and that below the ground by a negative integer first question an elevator descends into mineshaft at the rate of 5 metre per minute what will be it's position after one hour

Step-by-step explanation:

The elevator is descending, so its velocity is -5 m/min.  After 1 hour (or 60 minutes), the position is:

x = (-5 m/min) (60 min)

x = -300 m

It's position after one hour is -300 meters.

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !