Suppose that 50% of all adults regularly consume coffee, 65% regularly consume carbonated soda, and 45% regularly consumes both coffee and soda. (a) what is the chance a randomly selected adult regularly drinks coffee but doesn't drink soda?

There is a chance of 5% of adult regularly drinks coffee but doesn't drink soda.

Step-by-step explanation:

Since we have given that

Probability of all adults consume coffee P(C) = 50%

Probability of all adults consume carbonated soda P(S) = 65%

Probability of all adults consumes both coffee and soda P(C∩S) = 45%

We need to find the probability that adult regularly drinks coffee but doesn't drink soda.

So, it is talking about difference of sets in which we consider only one set completely i.e. it contains all element of one set but never contains any element of another set.

Here, P( Coffee - Soda) = P(C)-P(C∩S)

Hence, there is a chance of 5% of adult regularly drinks coffee but doesn't drink soda.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it