4. let f r-z defined by f(x)= 5 |. show that f is not one-to-one by exhibiting a counterexample. 5 pts. counterexample: let y -2 the tt 2 such that 5 2 10 shows that 5 all evel intqeus renot to-one one note 1.2, 1. 3 er and 12/3 -5 you shad fat f2) = f(l3 c(t001'1331) let f: r-r defined by f(z) = x2 - 2. show that f is not onto by exhibiting a counterexample. [you cannot use the reason that the codomain the range]. note 5. 5 pts. counterexample: 36e r, he codma 2 bat fz)= x ryou shw fhat kr, dhe domain

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

soo this can be solve by using the formula:

f = p( 1 + i)^ n

where f is the future profit

p is the initial profit

i is the percent increase

n is the number of years

a . f = 30000 ( 1.05)^n

b. f = 30000 ( 1.05)^15

f = $62,368

c.

step-by-step explanation:

simple you would first have to get   a negative number where as 1 to be multiplied by 24 and then you would have to multiply 6 time 4 and then repeat that process until you reach your term