38 -2 8 and b = 7 7 2. let vi , v2 1 v3 = -3 6 cob 3 10 a. find the norms of v, v2, and v3 b. normalize each of v1, v2, and v3 to unit vectors. call them q, q2, and q3. c. show that {v1, v2, v3} form an orthogonal d. let m be the matrix with columns v1, v2, and v3. solve mx =b using dot products. set. row reduction, (no e. let q be the matrix with columns qi, q2, and q3. calculate qtq. determinants.) no f. calculate the angle between vi and b, you may leave your answer in the form of an arccos

the answer is mc^1-1jpeg

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

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