Alarge company must hire a new president. the board of directors prepares a list of five candidates, all of whom are equally qualified. two of these candidates are members of a minority group. to avoid bias in the selection of the candidate, the company decides to select the president by lottery. a. what is the probability one of the minority candidates is hired?

0.4

Step-by-step explanation:

Given : The number of candidates are equally qualified for President = 5

The number of candidates are members of a minority group =2

Since , to avoid bias in the selection of the candidate, the company decides to select the president by lottery. Here the chances of each candidates is same.

The probability one of the minority candidates is hired is given by :-

Hence, the  probability one of the minority candidates is hired =0.4

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.