Aball is thrown vertically upward. after t seconds, its height h (in feet) is given by the function h(t) = 60t - 16t^2 . what is the maximum height that the ball will reach?
do not round your answer.

56.25 feet.

Step-by-step explanation:

For a Quadratic function in the form , if then the parabola opens downward.

Rewriting the given function as:

You can identify that

Since then the parabola opens downward.

Therefore, we need to find the vertex.

Find the x-coordinate of the vertex with this formula:

Substitute values:

Substitute the value of "t" into the function to find the height in feet that the ball will reach. Then:

the f

last graph i believe

step-by-step explanation:

worked it out i believe