We are given that lines a and c intersect at point s. translate line a down line c until period s reaches point q. call the new line through q line b. because translations preserve orientation, lines a and b are because translations preserve angle measure, angle a rsu is congruent to angle rqr. for the same reason, angle rsu is congruent to angle rqt, angle psu is congruent to angle pqr, and angle pst is congruent to angle pqt. each of the angle pairs are corresponding angles. therefore, corresponding angles are congruent.

p = 6s

step-by-step explanation:

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2

it's 100

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

  n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the  14th  row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

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