Urgent me with this math question

The image is (0 , -6)

Step-by-step explanation:

* Lets explain some important facts

- When a point reflected across a line the perpendicular

 distance from the point to the line equal the perpendicular  

 distance from its image to the same line

- If the line of the reflection is horizontal then the perpendicular

 distance between the point and the line is y - y1 , and the

 perpendicular distance between the image and the line is y2 - y

- If point (x , y) reflected across the x- axis, then its image is (x , -y)

* Lets solve the problem

∵ Point (0 , 0) reflected across the line y = 3

∴ y = 3 and y1 = 0

∴ The distance between the point and the line is 3 - 0 = 3

∴ The distance between the image and the line also = 3

∴ y2 - 3 = 3 ⇒ add 3 to both sides

∴ y2 = 6

∴ The y-coordinate of the image is  6

∴ The image of point (0 , 0) after reflection across the line y = 3 is (0 , 6)

- The image of the point reflected across the x-axis, then change the

  sign of the y-coordinate

∴ The final image of point (0 , 0) is (0 , -6)

* The image is (0 , -6)

m∠vru = 80°

m∠urw = 15°

step-by-step explanation: