Apolynomial has been factored below, but some constants are missing.
3x^3+6x^2-24x=ax(x+b)(x+c)
what are the missing values of a, b, and c

a=3, b=4, and c=-2

Step-by-step explanation:

3x^3+6x^2-24x

Each of the three terms has a common factor of 3x.

3x(x^2+2x-8)

Now can you think of two numbers that multiply to be -8 and add to be 2?

How about 4 and -2? 4(-2)=-8 and 4+(-2)+2.

So the factored form of x^2+2x-8 is (x+4)(x-2).

We can check this by using foil.

First: x(x)=x^2

Outer: x(-2)=-2x

Inner:  4(x)=4x

Last: 4(-2)=-8

Add them up! This gives you x^2+2x-8 which is the desired result.

So the factored form of 3x^3+6x^2-24x is 3x(x+4)(x-2).

Comparing 3x(x+4)(x-2) to ax(x+b)(x+c) gives us  a=3, b=4, and c=-2

kjgfcvbjkl

step-by-step explanation:

sdfghjkl; vbnm,

just sum

10 + 10 = 20