Match each spherical volume to the largest cross sectional area of that sphere

Part 1) ------>

Part 2) ------>

Part 3) ------>

Part 4) ------>

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

The area of the circle is equal to

so

Solve for r

Find the volume of the sphere

The volume of the sphere is

For

substitute

Part 2) we have

The area of the circle is equal to

so

Solve for r

Find the volume of the sphere

The volume of the sphere is

For

substitute

Part 3) we have

The area of the circle is equal to

so

Solve for r

Find the volume of the sphere

The volume of the sphere is

For

substitute

Part 4) we have

The area of the circle is equal to

so

Solve for r

Find the volume of the sphere

The volume of the sphere is

For

substitute

The above answer is correct.

Step-by-step explanation: I got this right on Edmentum.

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)