Plz very urgent need to solve 2 problems

(3x-4y)^2 = 9x^2-24xy+16y^2

(3x+5)(3x-4) = 9x^2+3x-20

(3x-2)(9x^2+6x+4) = 27x^3-8

step-by-step explanation:

(3x-4y)^2 = (3x-4y)(3x-4y)

3x·3x= 3x^2 & 3x·-4y= -12xy & -4y·3x= -12xy & -4y·-4y= 16y^2

so, 3x^2-12xy-12xy+16y^2

combine like

3x^2-24xy+16y^2

step-by-step explanation:

x-intercept:

(

−

1

+

√

7

,

0

)

,

(

−

1

−

√

7

,

0

)

y-intercept:

(

0

,

−

6

)

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