13 points tanfin12 2.6.028. 6. consider the following system of equations. x2 +x3 = bi x1 + x2 +x3 b2 x1- x1 2x2-x3 b3 (a) write the system of equations as a matrix equation. bi 1 1 1 x1 -1 b2 x2 1 -2 -1 by x3 (b) solve the system of equations by using the inverse of the coefficient matrix. (i) where bi 4, b2 -4 , b3 0 (x1, x2, x3) (ii) where bi 0, bz =3, b3 =-11 (xi, x2, need ? read it watch it submit answer save progress viewing saved work revert to last response practice another version 7. o-1 points tanfin12 2.6.038. find the matrix a if 4 1 1 3 a=

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation: