For mutually exclusive events upper r 1? , upper r 2? , and upper r 3? , we have ? p(upper r 1? )=0. p(upper r 2? )=0.4? , and ? p(upper r 3? )=0.55. ? also, p(q? | upper r 1? )=0.4? , ? p(q | upper r 2? )=0.3? , and? p(q | upper r 3? )=0.4. find ? p(upper r 1 ? | q).

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

56

step-by-step explanation:

ome people is not even worth it to even try it in the air.

step-by-step explanation:

you'll have to attache the image of the bar graph in order for us to answer : )

step-by-step explanation: