Solve the ivp: y" - 5y' + 4y = 0, y(0) = -3, y'(0) = 3 y = 6/5 e^4x y = 2e^4x - 5e^x y = 3e^-x y = -5e^-4x + 2e^-x

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step-by-step explanation:

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given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation:

the answer on e2020 was d.