The probability that a train leaves on time is 0.8. the probability that the train arrives on time and leaves on time is 0.24. what is the probability that the train arrives on time, given that it leaves on time?

Answer is 0.3

Step-by-step explanation:

Let the probability that the train arrives on time. = p

The probability that the train leaves on time = 0.8

The probability that the train leaves on time and arrives on time = 0.24

Then the equation will be:

0.8 * p = 0.24

Move the constant value to the R.H.S

p = 0.24/0.8

p = 0.3

Thus the probability is 0.3

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8