Drag the tiles to the correct boxes to complete the pairs. not all tiles will be used.
match each graph with the function it represents.

Graph A → y=√x.

Graph B → y=(√x) - 1.

Graph C → y=√(x-1).

Graph D → y= -√x.

Graph E → y= -√(x-1)

Step-by-step explanation:

The graph 'A' intercepts the y-axis at (0, 0). Therefore it belongs to the function y=√x.

The graph 'D' is exactly the same graph 'A' but reflected across the x-axis. Therefore, it belongs to the function y=-√x.

The function 'C' is exactly the same function y=√x but translated one unit to the right, therefore, the solution function is y=√(x-1)

The graph 'E' is exactly the same graph 'C' but reflected across the x-axis, therefore the function is: y= -√(x-1)

In the options you have two times the function y=√x. I assume that's a mistake. The graph 'B' corresponds to y = (√x) - 1

Part 1) -----> Graph C

Part 2) ----> Graph D

Part 3) -----> Graph A

Part 4) ---> Graph E

Step-by-step explanation:

Part 1) we have

Find the domain of the function

The radicand must be positive

so

Solve for x

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

Find the range

For x=1

so

The range is the interval ----> [0,∞)

All real numbers greater than or equal to 0

therefore

The function represent Graph C

Part 2) we have

Find the domain of the function

The radicand must be positive

so

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

Find the range

For x=0

so

The range is the interval ----> (-∞,0]

All real numbers less than or equal to 0

therefore

The function represent Graph D

Part 3) we have

Find the domain of the function

The radicand must be positive

so

Solve for x

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

Find the range

For x=0

so

The range is the interval ----> [0,∞)

All real numbers greater than or equal to 0

therefore

The function represent Graph A

Part 4) we have

Find the domain of the function

The radicand must be positive

so

Solve for x

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

Find the range

For x=1

so

The range is the interval ----> (-∞,0]

All real numbers less than or equal to 0

therefore

The function represent Graph E

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)