The radius of earth is 6400 km. the distance of the moon from the earth's surface is 38 km. find the radius of the moon which subtends an angle of 20'at the centre of the earth

1100 km

Step-by-step explanation:

The problem doesn't clearly state whether the 380,000 km is from the Earth's surface to the moon's center, or to the moon's surface.  Since we'll be rounding to 2 significant figures, it's not enough to make a difference, so I'll assume it's to the moon's center.

Draw circle representing the moon and earth.  Draw tangent lines from the earth's center to the edge of the moon.  The angle between these lines is the subtended angle.  Now draw a line representing the moon's radius from the center of the moon to the point where the tangent line intersects.  Notice this forms a right angle.

(See attached diagram)

Using trigonometry:

sin(θ/2) = r / (R + h)

r = (R + h) sin(θ/2)

Given that R = 6400 km, h = 380,000 km, and θ = 20' = 1/3 degrees:

r = (6400 + 380000) sin(1/6 °)

r = 1100

The moon's radius is 1100 km.

3

step-by-step explanation:

divide 13.5 by 9 to get the scale factor. it equals 1.5

2 * 1.5 = 3

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: