given:
bc⊥ac
m∠bac = 32°
use the given information to determine m∠cde.
32°
58°
68°
90°

Option B, 58°

Step-by-step explanation:

In the given figure AB ║ CD and BC ║ DE ( given )

Since BC ║ DE and BC ⊥ AC

So DE will also be perpendicular to CE

m ∠ BAC = 32° [given]

Since AB ║ CD and line AE is transverse

Then ∠BAC ≅  ∠DCE ≅ 32°

Now in ΔDEC.

∠DCE + ∠CED + ∠EDC = 180°

32° + 90° + ∠EDC = 180°

122° + ∠EDC = 180°

∠EDC = 180 -122

          = 58°

Option B, 58° is the answer.