Assume that when adults with smartphones are randomly selected, 51% use them in meetings or classes. if 11 adult smartphone users are randomly selected, find the probability that fewer than 5 of them use their smartphones in meetings or classes.

The probability is 0.2356.

Step-by-step explanation:

Let X is the event of using the smartphone in meetings or classes,

Given,

The probability of using the smartphone in meetings or classes, p = 51 % = 0.51,

So, the probability of not using smartphone in meetings or classes, q = 1 - p = 1 - 0.51 = 0.49,

Thus, the probability that fewer than 5 of them use their smartphones in meetings or classes.

P(X<5) = P(X=0) + P(X=1) + P(X=2) + P(X=3)+P(X=4)

Since, binomial distribution formula is,

Where,

Here, n = 11,

Hence,  the probability that fewer than 5 of them use their smartphones in meetings or classes

there is no graph so i cant sorry

step-by-step explanation: