![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{we know that } \begin{cases} h=2\\ k=-4 \end{cases}\implies y=a(x-2)^2-4 \\\\\\ \textit{we also know that } \begin{cases} y = -3\\ x = -3 \end{cases}\implies -3=a(-3-2)^2-4\implies 1=a(-5)^2 \\\\\\ 1=25a\implies \boxed{\cfrac{1}{25}=a}](/tpl/images/0079/1406/8720b.png)
The vertex of this parabola is at (2,-4). when the y value is -3, the x-value is
-3. what is t...
Mathematics, 12.07.2019 01:20 Kareemgreen1237
The vertex of this parabola is at (2,-4). when the y value is -3, the x-value is
-3. what is the coefficient of the squared term in the parabola's equation?
Answers: 1
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