Anew drug on the market is known to cure 20% of patients with breast cancer. if a group of 20 patients is randomly
selected, what is the probability of observing, at most, one patient who will be cured of breast cancer?
a• (20)/1 (0-20)^1 (0.80)^19
b. 1-(20)/1 (.20)'(0.230)
c. (20)/0( .80)^20+(20/)^1(.80)^19
d • (20)/0 (.80)^20
e. 1-(20/)^20
01-(20)10.2010

It's actually C

Step-by-step explanation:

don't forget about the probability of 0 too

you have to add the two probability formulas

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316