Find the equation of the line through (2,9)(1,,-6)

y=(3/2)x+6

If your equation is in a different form, let me know.

Step-by-step explanation:

So the slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.

Parallel lines have the same slope, m (different y-intercept (b) though).

So we need to find the slope going through (1,6) and (-7,-6).

To do this you could use .

Or, what I like to do is line the points up vertically and subtract vertically then put 2nd difference over first difference. Like so:

(  1  ,  6)

-( -7,  -6)

---------------

  8     12

So the slope of our line is 12/8.

Let's reduce it! Both numerator and denominator are divisible by 4 so divide top and bottom by 4 giving 3/2.

Again parallel lines have the same slope.  

So we know the line we are looking for is in the form y=(3/2)x+b where we don't know the y-intercept (b) yet.

But we do know a point (x,y)=(2,9) that should be on our line.

So let's plug it in to find b.

y=(3/2)x+b  with (x,y)=(2,9)

9=(3/2)2+b

9=3       +b

Subtract 3 on both sides:

9-3=b

6=b

So the equation in slope intercept form is y=(3/2)x+6

first one because it can't have a fraction in it

step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: