Use a graphing utility to zoom in on the maximum point of the revenue function in the example. (use a setting of 1.62 ≤ x ≤ 1.65 and 43.5 ≤ y ≤ 43.6.) use the trace feature to improve the accuracy of the approximation obtained in the example. do you think this improved accuracy is appropriate in the context of this particular problem? does it change the price?

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

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i don't know

step-by-step explanation: