Given h(x) = x-3 and f(x) = x3-x2-x-15 is h(x) a factor of f(x)?

Yes.

Step-by-step explanation:

To see if h is a factor of f, we can use the factor theorem.

h(x)=x-3 has a zero at x=3 because h(3)=3-3=0.

So we want to see if the zero of h is a zero of f.

Is x=3 a zero of f?

You can check using synthetic division or just plug in 3.

Let's do both.

If you use synthetic you are trying to see if you get a remainder of 0.

If you plug it in you are trying to see if you get 0 as the output when plugging your input 3.

Let's do synthetic first:

Since we are checking to see if x=3 is a zero, that will go on the outside:

3 |  1   -1  -1   -15

 |        3   6    15

-

     1    2   5     0

So yep the remainder is 0 so the answer is yes.

Let's plug it in:

f(3)=3^3-3^2-3-15

f(3)=27-9-3-15

f(3)=18-3-15

f(3)=15-15

f(3)=0

The result is 0 so the answer is yes.

You pick your favorite way here.

answer: $201

step-by-step explanation: to get the answer, you first get 3 nieces that he sold and multiply it by 67 and get $201, so he earned $201 selling his nieces.

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk