If segment ba is congruent to segment bc and m∠bca = 44°, what is m∠cxa?

m∠CXA=136°

Step-by-step explanation:

In this problem we know that

Triangle ABC is an isosceles triangle

so

m∠BCA=m∠BAC=44°

Segment AD  bisect angle  m∠BAC

so

m∠BAX=m∠XAC=m∠BAC/2=22°

Segment CE  bisect angle  m∠BCA

so

m∠BCX=m∠XCA=m∠BCA/2=22°

Remember that

The sum of the interior angles of triangle must be equal to 180 degrees

so

In the triangle AXC

m∠XCA+m∠XAC+m∠CXA=180°

we have

m∠XCA=22°

m∠XAC=22°

substitute

22°+22°+m∠CXA=180°

m∠CXA=180°-44°=136°

step-by-step explanation:

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