Plz asap 30 !
a farmer in china discovers a mammal hide that contains 70% of its original amount of c-14.
n=n0e^kt
no=amount of c-14 at time t
k=0.0001
t=time in years
find the age of the mammal hide to the nearest year.

The age of the mammal hide is  3,567 years old.

Given,

N = NOe^kt

Here

N - amount after t years

No = Original amount

K = 0.0001

t = number of years

Now

Now Take the logarithm of both sides:

t = 3566.74

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Substitute the given numbers for their letters in the equation:

N = NOe^kt

N - amount after t years

No = Original amount

K = 0.0001

t = number of years

Substitute the given numbers for their letters in the equation:

0.70 = 1 * e^-0.0001t

Take the logarithm of both sides:

log0.70 = loge^-0.0001t

-0.1549 = -0.0001t * 0.43429

t = -0.1549 / (-0.0001 * 0.43429)

t = 3566.74

Rounded to the nearest year = 3,567 years old.

whatever you can spend with $11.53 or under.

step-by-step explanation:

20 - 8.47 = 11.53. take away the money he used for lunch from the starting amount of 20.

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step-by-step explanation: