The system of equations y=2x-1 and y=-1/4x+3 is shown on the graph below. what is a reasonable estimate for the solution?

Something close to (1.8,2.6)

Step-by-step explanation:

y=2x-1

y=-1/4 x+3

Since y=2x-1 and y=-1/4 x +3 then 2x-1=-1/4 x +3.

I'm going to multiply both sides by 4 to get rid of the fraction:

8x-4=-x+12

Add x on both sides:

9x-4=12

Add 4 on both sides:

9x=16

Divide both sides by 9:

x=16/9 is approximately 1.8 when put into calculator.

Now if x=16/9 and y=2x-1, then y=2(16/9)-1=32/9-1=32/9-9/9=(32-9)/9=23/9.

y=23/9 is approximately 2.6 when put into calculator.

So we are looking for an ordered pair pretty close to (1.8,2.6).

The graph is shown to you so I will put one here as well:

the answer will be b x² +x-1

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204