Find a polynomial f(x) of degree 4 that has the following zeros.
0, -4, (multiplicity ), 2
leave your answer in factored form.

Step-by-step explanation:

Since there is a multiplicity at x=-4, that would meant that that part of the factor would have to have an even degree. This means that it would have to be 2.

This would give you

Step-by-step explanation:

The zeros of the polynomial are all the values of x for which the function

In this case we know that the zeros are:

,

Now we can write the polynomial as a product of its factors

Note that the polynomial is of degree 4 because the greatest exponent of the variable x that results from multiplying the factors of f(x) is 4

l.jnl.j/n.m,lm,

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.