(b) prove that there is a unique integer n for which 2n^2-3n-2=0.

The only integer solution is n1=2

Step-by-step explanation:

Let's find the answer by using the following equation applied to quadratic polynomials with the form :

For our case , a=2, b=-3, and c=-2, so:

In conclusion, although there are 2 roots (n1, n2), only one of them is an integer, which is n1=2.

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

£56

step-by-step explanation: