Let the function f(x) have the form fx) = acos(x+c). to produce a graph that
matches the one shown below, what must the value of c be?

The value of C = 2 ⇒ answer C

Step-by-step explanation:

* Lets explain how to solve the problem

- The function g(x) = cos(x) represented by the red graph

- Lets revise the transformation of the cosine function

- f(x) = A cos(B(x + C)) + D , where

# amplitude is A

# period is 2π/B

# phase shift is C (positive is to the left)

# vertical shift is D

- The function f(x) = A cos(x + C) represented by the purple graph

# A is the amplitude

# C is the phase shift

- g(x) is the parent function of f(x)

- From the graph:

∵ The greatest value of g(x) in the red graph is at x = 0

∵ The greatest value of f(x) in the purple graph is at x = -2

- That means the graph sifted 2 units to the left

∴ The red graph shifted two units to the left in the purple graph

∵ The phase shift to the left is positive

∵ C is the phase shift

∴ The value of C = 2

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

there is no question content here, but you for the free points! : d